MCQ
$\lim_\limits{\text{x} \rightarrow 0}\frac{2\text{x}^2+3\text{x}+4}{2}=$
  • $2$
  • B
    $1$
  • C
    $3\sqrt{5}$​
  • D
    $2\sqrt{5}$

Answer

Correct option: A.
$2$
As their is not any $x$ term in the denominator,
we can directly substitute the value of $x$ as $0.$
Thus, we have $\lim_\limits{\text{x} \rightarrow 0}\frac{2\text{x}^2+3\text{x}+4}{2}$
$=\frac { 2.0+3.0+4 }{ 2 }$
$=\frac{4}{2}$
$=2$

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