MCQ
Litharge is chemically
- ✓$PbO$
- B$Pb{O_2}$
- C$P{b_3}{O_4}$
- D$Pb{(C{H_3}COO)_2}$
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$(1) Ca_3P_2 + H_2O \to$
$(2)$ ${H_3}P{O_3}\xrightarrow{\Delta }$
$(3) P_4 + NaOH \to$
$(4)$ ${H_3}P{O_4}\xrightarrow{\Delta }$
$(5) HNO_3 + P_4O_{10} \to$
$(6)$ $P_4+HNO_3 \to$
$A \,|\, A^+\, (xM)\, ||\, B^+ \,(yM)\, |\, B$
The $emf$ measured is $+ 0.20\, V.$ The cell reaction is

