MCQ
${M^{ + 3}}$ ion loses $3{e^ - }$. Its oxidation number will be
- A$0$
- B$+3$
- ✓$+6$
- D$-3$
✓
Answer
Correct option: C.
$+6$
(c) $2$ $×$ No. of ${e^ - }$ losses = Oxi. no.
$2 \times 3{e^ - } = + 6$.
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