MCQ
Magnifying power of a simple microscope is (when final image is formed at $D = 25\; cm$ from eye)
- A$\frac{D}{f}$
- ✓$1 + \frac{D}{f}$
- C$1 + \frac{f}{D}$
- D$1 - \frac{D}{f}$
we have, $\frac{1}{-D}-\frac{1}{-u}=\frac{1}{f}$
i.e., $\frac{D}{u}=1+\frac{D}{f}$
So magnifying power $=\frac{D}{u}=\left(1+\frac{D}{f}\right)$
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