MCQ
Major product of reaction :
  • A

  • B

  • C


Answer

Correct option: D.

d

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

Ozonolysis of $ClO _2$ produces an oxide of chlorine. The average oxidation state of chlorine in this oxide is. . . . . 
$STATEMENT-1$: Bromobenzene upon reaction with $\mathrm{Br}_2 / \mathrm{Fe}$ gives $1,4$ -dibromobenzene as the major product. and

$STATEMENT-2$: In bromobenzene, the inductive effect of the bromo group is more dominant than the mesomeric effect in directing the incoming electrophile.

The rate constants for decomposition of acetaldehyde have been measured over the temperature range $700-1000\, K$. The data has been analysed by plotting $ln\, k\,$vs$\,\frac{10^{3}}{ T }$ graph. The value of activation energy for the reaction is $......\,kJ mol ^{-1}$. (Nearest integer) (Given : $R =8.31\, J \,K ^{-1} \,mol ^{-1}$ )
For $0.1\,M $ solution, the colligative property will follow the order
Which of the following alkaline earth metal sulphates has hydration enthalpy higher than the lattice enthalpy?
For certain chemical reaction $X \rightarrow Y$, the rate of formation of product is plotted against the time as shown in the figure. The number of Correct statement/s from the following is $.......$.

$(A)$ Over all order of this reaction is one

$(B)$ Order of this reaction can't be determined

$(C)$ In region$-I$ and $III$, the reaction is of first and zero order respectively

$(D)$ In region$-II$, the reaction is of first order

$(E)$ In region$-II$, the order of reaction is in the range of $0.1$ to $0.9$.

What is the functional group in alcohol?
A non-metal $M$ forms $MCl_3 , M_2O_5$ and $Mg_3M_2$ but does not form $MI_5.$ Then incorrect statement regarding non-metal $M$ is
Product  $(B)$ of the reaction is
What volume of decimolar solution should be mixed in a solution of same solute $(0.5 \,M,\,200\, ml)$ to make it $0.25\,molar$ ........ $ml$.