Masses of three wires of copper are in the ratio of 1 : 3 : 5 and their lengths are in the ratio of 5:3:1.

Q: Masses of three wires of copper are in the ratio of $1 : 3 : 5$ and their lengths are in the ratio of $5:3:1.$ The ratio of their electrical resistances are

d $R \propto \frac{{{l^2}}}{m}$ $ \Rightarrow $${R_1}:{R_2}:{R_3} $$= {\left( {\frac{{{l_1}}}{{{m_1}}}} \right)^2}:{\left( {\frac{{{l_2}}}{{{m_2}}}} \right)^2}:{\left( {\frac{{{l_3}}}{{{m_3}}}} \right)^2}$ $ = 25:3:\frac{1}{5} \Rightarrow 125:15:1$

SECTION - A [PHYSICS - MCQ]

GSEB - English Medium

Masses of three wires of copper are in the ratio of $1 : 3 : 5$ and their lengths are in the ratio of $5:3:1.$ The ratio of their electrical resistances are

A$1:3:5$
B$5:3:1$
C$1:15:125$
D$125:15:1$

AIPMT 1988, Medium

STD 11 Science
NEET
STD 12 - 3. current electricity
Physics

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