The Kirchhooff's first law $\left(\sum i=0\right)$ and second law ( $\left.\sum i R=\sum E\right)$, where the symbols have their usual meanings, are respectively based on
A
conservation of electric charge and energy respectively
B
conservation of charge, conservation of momentum
C
conservation of energy, conseration of charge
D
conservation of momenturm, conservation of charge.
AIPMT 2006,AIEEE 2006, Easy
Download our app for free and get started
A
conservation of electric charge and energy respectively
a Kirchhoff's first law ofelectrical circuit is based on conservation of charge and Kirchhoff's second law of electrical circuit is based on conservation of energy.
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Twelve wires each having resistance $2 \Omega$ are joined to form a cube. A battery of $6 \mathrm{~V}$ emf is joined across point $\mathrm{a}$ and $\mathrm{c}$. The voltage difference between $e$ and $f$ is.______.V.
In the potentiometer circuit as shown in the figure, the balance length $Al = 60\ cm$ when switch $S$ is open. When switch $S$ is closed and the value of $R$ is $5W$ the balance length $Al' = 50 cm.$ The internal resistance of the cell $C'$ is : .............. $\Omega$
In an experiment to find $emf$ of a cell using potentiometer, the length of null point for a cell of emf $1.5\,V$ is found to be $60\,cm$. If this cell is replaced by another cell of $emf\; E$. the length-of null point increases by $40\,cm$. The value of $E$ is $\frac{x}{10} V$. The value of $x$ is $............$
Figure shows a part of an electric circuit. The potentials at points $a , b$ and $c$ are $30\,V , 12\,V$ and $2\,V$ respectively. The current through the $20 \Omega$ resistor will be $........\,A$
The current $i_1$ and $i_2$ through the resistor $R_1 (= 10\,\Omega )$ and $R_2 (=30 \,\Omega )$ in the circuit diagram with $E_1 = 3\,V, E_2 = 3\,V$ and $E_3 = 2\,V$ are respectively:
Two cells when connected in series are balanced on $8\;m$ on a potentiometer. If the cells are connected with polarities of one of the cell is reversed, they balance on $2\,m$. The ratio of $e.m.f.$'s of the two cells is