MCQ
Match the column :-

 $\begin{array}{|l|l|l|l|} \hline & Column\,I & & Column\,II \\ & (Reduction\,process) & & (Charge\,required) \\ \hline (a) & 1\,mol\,of\,MnO_4^-\,to\,Mn^{2+} & (p) & 193000\,\,C \\ \hline (b) & 1\,\,mole\,of\,Cr_2O_7^{2-}\,to\,Cr^{3+} & (q) & 289500\,\,C \\ \hline (c) & 1\,\,mole\,of\,Sn^{4+}\,to\,Sn^{2+} & (r) & 482500\,\,C \\ \hline (d) & 1\,mole\,of\,Al^{3+}\,to\,Al & (s) & 579000\,\,C \\ \hline \end{array}$

  • A
    $a \to p, \,b \to r, \,c \to q, \,d \to s$
  • B
    $a \to r, \,b \to s,\, c \to q, \,d \to p$
  • C
    $a \to s, \,b \to q, \,c \to p, \,d \to r$
  • $a \to r, \,b \to s, \,c \to p, \,d \to q$

Answer

Correct option: D.
$a \to r, \,b \to s, \,c \to p, \,d \to q$
d
Equivalents $=$ Mole $\times(n \text { -factor })=$ Faraday

$\mathrm{MnO}_{4}^{-} \rightarrow \mathrm{Mn}^{+2} ; 1$ mole $\times 5=5 \mathrm{F}=482500\, \mathrm{C}$

$\mathrm{Cr}_{2} \mathrm{O}_{7}^{-2} \rightarrow \mathrm{Cr}^{+3} ; 1$ mole $\times 6=6 \mathrm{F}=579000\, \mathrm{C}$

$\mathrm{Sn}^{+4} \rightarrow \mathrm{Sn}^{+2} ; 1$ mole $\times 2=2 \mathrm{F}=193000\, \mathrm{C}$

$\mathrm{Al}^{+3} \rightarrow \mathrm{Al} ; 1$ mole $\times 3=3 \mathrm{F}=289500\, \mathrm{C}$

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