MCQ
$\mathop {\lim }\limits_{n \to \infty } \left[ {\frac{1}{{1 - {n^2}}} + \frac{2}{{1 - {n^2}}} + \frac{3}{{1 - {n^2}}} + ........ + \frac{n}{{1 - {n^2}}}} \right] =$
  • A
    $0$
  • $ - \frac{1}{2}$
  • C
    $1/2$
  • D
    None of these

Answer

Correct option: B.
$ - \frac{1}{2}$
b
(b) $\mathop {\lim }\limits_{n \to \infty } \,\left[ {\frac{1}{{1 - {n^2}}} + \frac{2}{{1 - {n^2}}} + ..... + \frac{n}{{1 - {n^2}}}} \right]$

$ = \mathop {\lim }\limits_{n \to \infty } \,\frac{{\Sigma n}}{{1 - {n^2}}} = \frac{1}{2}\,\,\mathop {\lim }\limits_{n \to \infty } \,\,\,\frac{{{n^2} + n}}{{1 - {n^2}}} = - \frac{1}{2}$.

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