MCQ
$\mathop {\lim }\limits_{x \to 0} \frac{{1 - \cos (1 - \cos x)}}{{x\tan x - {x^2}}}$ =
- A$- \frac{8}{3}$
- B$- \frac{3}{8}$
- ✓$\frac{3}{8}$
- D$\frac{8}{3}$
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