MCQ
$\mathop {\lim }\limits_{x \to 0} \,\frac{{x\,\cot \,\left( {4x} \right)}}{{{{\sin }^2}\,x\,{{\cot }^2}\,\left( {2x} \right)}}$ =
- A$0$
- B$2$
- C$4$
- D$1$
$ = \frac{{4x}}{{\sin 4x}}.\frac{{\cos 4x}}{{{{\cos }^2}2x}}{\cos ^2}x$
$ \Rightarrow 1\,\,\,\,\,as\,\,\,x \to 0$
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.