MCQ
Methyl amine reacts with $HN{O_2}$ giving
- A$C{H_3}O - N = O$
- B$C{H_3} - O - C{H_3}$
- C$C{H_3}OH$
- ✓$(a)$ and $(b)$ both
$2C{H_3}N{H_2} + 2HN{O_2} \to C{H_3} - O - C{H_3} + 2{N_2} + 3{H_2}O$
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$I ^{-}+ ClO _3^{-}+ H _2 SO _4 \longrightarrow Cl ^{-}+ HSO _4^{-}+ I _2$
The correct statement(s) in the balanced equation is/are:
$(A)$ Stoichiometric coefficient of $HSO _4^{-}$is 6 .
$(B)$ lodide is oxidized.
$(C)$ Sulphur is reduced.
$(D)$ $H _2 O$ is one of the products.