MCQ
$[Mn(CO)_4 NO]$ is diamagnetic because
- A$Mn$ metal is diamagnetic in free state
- B$Mn$ is in $+1$ oxidation state in this complex
- C$NO$ is present as positive ligand
- ✓All of the above
✓
Answer
Correct option: D.
All of the above
d
$[\overset{+1}{\mathop{Mn}}\,{{(CO)}_{4}}(N{{O}^{-}})]:$ Paramagnetic due to presence of unpaired $e^-s$ in $NO^-$
$[\overset{+1}{\mathop{Mn}}\,{{(CO)}_{4}}(N{{O}^{-}})]:$ Paramagnetic due to presence of unpaired $e^-s$ in $NO^-$
$[\overset{-1}{\mathop{Mn}}\,{{(CO)}_{4}}(N{{O}^{+}})]:$ No unpaired $e^-$ either on ligands or on $\overset{-1}{\mathop{Mn}}$ hence it is diamagnetic
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