MCQ
Molarity of $4\% $ $NaOH$ solution is ......... $M$.
- A$0.1$
- B$0.5$
- C$0.01$
- ✓$1.0$
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(Where the constant $B$ is positive)
$ + \frac{1}{2}\frac{{d\left[ C \right]}}{{dt}} = - \frac{1}{3}\frac{{d\left[ D \right]}}{{dt}} = + \frac{1}{4}\frac{{d\left[ A \right]}}{{dt}} = \frac{{ - d\left[ B \right]}}{{dt}}$
the reaction is
$(I)$ the nature of the ligand
$(II)$ the charge on the metal ion
$(III)$ whether the metal is in the first, second or third row of the transition elements
