Molecular formula of ethanol is?

$\begin{array}{*{20}{c}}
{\begin{array}{*{20}{c}}
{\,\,\,\,C{H_2} - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}} \\
{\,\,CH - O - C{H_3}} \\
{|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,} \\
{\,\,C{H_2} - O - C{H_3}}
\end{array}\xrightarrow{{HI(excess)}}$

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$17.4\%\, (w/v)$ $K_2SO_4 (Mw=174\,g/mol)$ solution at $27\,^oC$ is isotonic to $4\% \,(w/v)\, NaOH$ solution at same temperature. If $NaOH$ is $100\%$ ionized, what is $\%$ ionization of $K_2SO_4$ in aqueous solution .......... $\%$.

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Which compound is not inflammable

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The reaction of an aldehyde with hydroxylamine gives a product which is called

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In the following sequence

$CH_3CH_2Cl \xrightarrow{NaCN}(i)\xrightarrow{Ni/{{H}_{2}}}(ii)\xrightarrow{acetic\,anhydride}(iii)$ , Product $(iii)$ is

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The dehydrobromination of $2-$ bromobutane gives $C{H_3}CH = CHC{H_3}.$ The product is

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