MCQ
Monochromatic light rays parallel to $x$ -axis strike a convex lens $AB$. If the lens oscillates such that $AB$ tilts upto a small angle $\theta$ (in radian) on either side of $y$ -axis, then the amplitude of oscillation of image will be ($f =$ focal length of the lens):


- A$f\, sec \, \theta$
- B$f\, sec^2\, \theta$
- C$\frac{{{\text{f }}{\theta ^2}}}{2}$
- ✓$\frac{{{\text{f }}{\theta ^2}}}{4}$





