MCQ
Monochromatic light rays parallel to $x$ -axis strike a convex lens $AB$. If the lens oscillates such that $AB$ tilts upto a small angle $\theta$ (in radian) on either side of $y$ -axis, then the amplitude of oscillation of image will be ($f =$ focal length of the lens):
  • A
    $f\, sec \, \theta$
  • B
    $f\, sec^2\, \theta$
  • C
    $\frac{{{\text{f }}{\theta ^2}}}{2}$
  • $\frac{{{\text{f }}{\theta ^2}}}{4}$

Answer

Correct option: D.
$\frac{{{\text{f }}{\theta ^2}}}{4}$
d

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