MCQ
Number of neutron in ${C^{12}}$ is
- ✓$6$
- B$7$
- C$8$
- D$9$
Neutrons $=$ Mars numbes $-$ Protons
$=12-6$
Neutrons $=6$
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$C{H_3} - CH = CH - CH\left( {OH} \right) - Me$ is
$\Delta S_A^o = 100\frac{J}{{mol \times k}}$ $\Delta S_C^o = 200\frac{J}{{mol \times k}}$
$\Delta S_B^o = 120\frac{J}{{mol \times k}}$ $\Delta S_D^o = 150\frac{J}{{mol \times k}}$