MCQ
On the intervl $ (1,3)$, the function $f(x) = 3x + {2 \over x}$ is
  • A
    Strictly decreasing
  • Strictly increasing
  • C
    Decreasing in $ (2, 3) $ only
  • D
    Neither increasing nor decreasing

Answer

Correct option: B.
Strictly increasing
b
(b) $f(x) = 3x + \frac{2}{x}$

==> $f'(x) = 3 - \frac{2}{{{x^2}}}$

Clearly $f'(x) > 0$ on the interval $(1, 3)$ 

$f(x)$ is strictly increasing.

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Similar questions

$\int_{}^{} {{e^{x/2}}\sin \left( {\frac{x}{2} + \frac{\pi }{4}} \right)\;dx = } $
If $x = a \sec \theta, y = b \tan \theta$ then $\frac{d y}{d x}=$ ?
The area of the region $\{(\text{x},\text{y}):\text{x}^2+\text{y}^2\leq1\leq\text{x}+\text{y}\}$ is :
A tangent having slope of $-\frac{4}{3}$ to the ellipse $\frac{\text{x}^2}{18}+\frac{\text{y}^2}{32}=1$ ntersects the major and minor axes at points $A$ and $B$ respectively. If $C$ is the center of the ellipse, then area of the triangle $\text{ABC}$ is:
If $A =$ $\left( {\begin{array}{*{20}{c}}a&b\\c&d\end{array}} \right)$  satisfies the equation $x^2 - (a + d) x + k = 0$, then
$\int_{}^{} {\frac{{dx}}{{4{{\cos }^3}2x - 3\cos 2x}}} = $
Let $f ( x )=\min \{1,1+ x \sin x \}, 0 \leq x \leq 2 \pi$. If $m$ is the number of points, where $f$ is not differentiable and $n$ is the number of points, where $f$ is not continuous, then the ordered pair $( m , n )$ is equal to
Let $A$ be any $3 \times 3$ invertible matrix. Then which one of the following is not always true ?
If $f(x) = \cos \left( {{{\tan }^{ - 1}}\left( {\sin \left( {{{\cos }^{ - 1}}x} \right)} \right)} \right) + \sin \left( {{{\cot }^{ - 1}}\left( {\cos \left( {{{\sin }^{ - 1}}x} \right)} \right)} \right)$ has range $\left[ {m,M),} \right.$ then number of solutions of the equation $\operatorname{sgn} \left( {\left| {x - 1} \right| - 2} \right) = \ln \left| {x - 2} \right|$ is (where sgn denotes signum function)
Matrix $A = \left[ {\begin{array}{*{20}{c}}
  x&3&2 \\ 
  1&y&4 \\ 
  2&2&z 
\end{array}} \right]$, $xyz = 60$ and $8x + 4y + 3z = 20$, then $A.(Adj A)$ is equal to