HCF(24,20)=3 X+1, then X= (0,1,2) - Vidyadip

Question

$\operatorname{HCF}(24,20)=3 X+1$, then $X=$ $(0,1,2)$

✓

Answer

1

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "Fill In The Blanks[1 Marks ]" from Real Numbers→Real Numbers — all question types→Maths STD 10 question papers→Gujarat Board STD 10 question papers→Gujarat Board question paper generator→

Similar questions

The length of the minute hand of a clock is 14 cm. The area swept by the minute hand in 5 minutes is ____________ sq.cm.(154,$\frac{154}{3}$,77)

$L.C.M.$ $(12,15)$=_______ $(15,1,60)$

The probability of an event that cannot happen is ________. Such an event is called ________.

The graph of the quadratic polynomial $a x^2+b x+c$ (e.g. $\left.-4 x^2+4 x-1\right) a<0, b>0, c<0, a, b, c \in$ $R$ is......(Parabola open upwards and intersects X-axis in only one point, Parabola open downwards and intersects $X$-axis in one point, Parabola open upwards and intersects $X$-axis in two distinct point.)

$\tan ^2 \theta-\sec ^2 \theta=$………………...$(0<\theta<90)$ $(-3,-5,-1)$

The probability of an event which can occur sure is……….. This event is called………... (sure event, 1; 1, sure event; 0 , sure event)

The Probability of rain tomorrow is 0.657 . Then …………. is the probability that there will be NO rain tomorrow. $(0,0.343,0.433)$

Two lines are intersecting in one point, then this type of pair is_________ (inconsistent, consistent, infinity)

If the pair of linear equations $a_1 x+b_1 y+c_1=0$ and $a_2 x+b_2 y+c_2=0$ has unique solution then $ y=\ldots \ldots . . . . \quad\left(\begin{array}{l} \frac{c_1 a_2-c_2 a_1}{a_1 b_2-a_2 b_1}, \quad \frac{b_1 c_2-b_2 c_1}{a_2 b_2-a_2 b_1}, \frac{a_1 b_2-a_2 b_1}{1} \\ \text { where } a_1 b_2-a_2 b_1 \neq 0 a_1 b_2-a_2 b_1 \neq 0 \end{array}\right) $

$5,2,-1 \ldots-49$ is an arithmetic progression so it has ............. terms. $(19,20,21)$