MCQ
Oxidation number of $N$ in ammonium nitrate is
- A$+3$
- B$-3$
- ✓$-3$ and $+5$
- D$+5$
✓
Answer
Correct option: C.
$-3$ and $+5$
c
Ammonium nitrate $\longrightarrow \mathrm{NH}_{4} \mathrm{NO}_{3}$
Ammonium nitrate $\longrightarrow \mathrm{NH}_{4} \mathrm{NO}_{3}$
which can be written as $\mathrm{NH}_{4}^{+} \mathrm{NO}_{3}^{-}$ For $\mathrm{NH}_{4}^{+}$
Let oxidation state of $\mathrm{N}=\mathrm{x}$
we know that oxidation state of $\mathrm{H}=+1$
Sum of total oxidation state of all atoms $=$ Overall charge on the compound. $x+4 \times(1)=1$
$\mathrm{x}=-3$
Let oxidation state of $\mathrm{N}$ in $\mathrm{N} \mathrm{O}_{3}^{-}=\mathrm{y}$, we know that oxidation state of $\mathrm{O}=-2$
Applying above formula $y+3 \times(-2)=1$
$y=+5$
Oxidation state of $\mathrm{N}$ in $\mathrm{NH}_{4} \mathrm{N} \mathrm{O}_{3}=-3,+5$
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