MCQ
Oxidation state of chlorine in perchloric acid is
- A$-1$
- B$0$
- C$-7$
- ✓$+7$
$1 + x - 2 \times 4 = 0;\,\,1 + x - 8 = 0$
$x = 8 - 1 = + 7$ oxidation state.
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| List-I | List-II | ||
| (A) | Solution of chloroform and acetone | (I) | Minimum boiling azeotrope |
| (B) | Solution of ethanol and water | (II) | Dimerizes |
| (C) | Solution of benzene and toluene | (III) | Maximum boiling azeotrope |
| (D) | Solution of acetic acid in benzene | (IV) | $\Delta \mathrm{V}_{\text {mix }}=0$ |
Choose the correct answer from the options given below :
(Atomic mass : $C =12 ; H =1 ; O =16$ )