MCQ
Oxidation state of nitrogen in NH2OH is:
- A−3
- B−1
- C+2
- D3
Explanation:
Let x be the oxidation state of N in NH2OH.
Since the overall charge on the complex is 0, the sum of oxidation states of all elements in it should be equal to 0.
Therefore, x + 2 − 1 = 0 or, x = −1.
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$\left[\right.$ Given : $pK _{ b }\left( NH _3\right)=4.745$
$\log 2=0.301$
$\log 3=0.477$
$T =298\,K ]$
$NH_3(g) + O_2(g) \rightarrow NO(g) + H_2O(l)$
$NO(g) + O_2(g) \rightarrow NO_2(g)$
To obtain maximum mass of $NO_2$ from a given mass of mixture $NH_3$ and $O_2$, the ratio of mass of $NH_3$ to $O_2$ should be -