MCQ
Oxidation state of $‘S’ $ in ${H_2}S{O_3}$
- A$+3$
- B$+6$
- ✓$+4$
- D$+2$
$ + 2 + x - 2 \times 3 = 0$; $x = 6 - 2 = + 4$.
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
$\begin{array}{*{20}{c}}
H\\
|\\
{ClHC = HC - C - CH = CHCl}\\
|\\
{Cl}
\end{array}$