MCQ
Oxygen is not evolved on reaction of ozone with
- A${H_2}{O_2}$
- ✓$S{O_2}$
- C$Hg$
- D$KI$
✓
Answer
Correct option: B.
$S{O_2}$
b
(b) Ozone on treatment with $S{O_2}$ produce $S{O_3}$.
(b) Ozone on treatment with $S{O_2}$ produce $S{O_3}$.
$3S{O_2} + {O_3} \to 3S{O_3}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
The compound that does $NOT$ liberate $CO _2$, on treatment with aqueous sodium bicarbonate solution, is
→For the reaction, $2S{O_2}{\kern 1pt} (g)\, + \,{O_2}\,(g)\, \to \,2S{O_3}\,(g)$
→${\Delta _H}\, = \, - 57.2\,kJ\,mo{l^{ - 1}}$ and ${K_C} = 1.7\, \times \,{10^{16}}$
Which of the following statement is $INCORRECT$ ?
This conversion can be acheived by
In $[Ag (CN)_2]^-$, the number of $\pi $ bonds is
→The proteins which are insoluble in water are
Which of the following is not essential amino acid
The role of conc. ${H_2}S{O_4}$ in the esterification process is
→The product $P$ is :
→Match the four starting materials $( P , Q , R , S$ ) given in List $I$ with the corresponding reaction schemes $(I, II, III, IV)$ provided in List $II$ and select the correct answer using the code given below the lists. $Image$
→Codes: $ \quad P \quad Q \quad R \quad S$
Which, if any, of the following pairs of reagents could be used to prepare $2$ -phenyl- $2$ -butanol?
→