MCQ
Palmitic acid is
- A${C_{16}}{H_{31}}COOH$
- B${C_{17}}{H_{35}}COOH$
- ✓${C_{15}}{H_{31}}COOH$
- D${C_{17}}{H_{31}}COOH$
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Given $SO_3(g) + H_2O(l) \rightarrow H_2SO_4(l)$
$\Delta H = -130\,\, kcal\, mol^{-1}$
$SO_2(g) + 1/2O_2(g) \rightarrow SO_3(g)$
$\Delta H = -100 \,\,kcal\,\, mol^{-1}$
the enthalpy of formation of $H_2SO_4(l)$ would be ......$kcal\, mol^{-1}$