MCQ
Parallel rays are incident on a transparent sphere along its one diameter. After refrection these rays converge at the other end of this diameter the refractive index of the sphere is
- A$1$
- B$1.5$
- C$1.6$
- ✓$2 $
✓
Answer
Correct option: D.
$2 $
d
$\frac{\mu_{2}}{v}-\frac{\mu_{1}}{u}=\frac{\mu_{2}-\mu_{1}}{R}$
$\frac{\mu_{2}}{v}-\frac{\mu_{1}}{u}=\frac{\mu_{2}-\mu_{1}}{R}$
$\mathrm{v}=2 \mathrm{R}, \mathrm{u}=\infty, \mathrm{R}=+\mathrm{R}, \mu_{1}=1, \mu_{2}=\mu$
$\frac{\mu}{2 R}-\frac{1}{\infty}=\frac{\mu-1}{R} \Rightarrow \mu=2$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
What should be the angle between two plane mirrors so that whatever be the angle of incidence, the incident ray and the reflected ray from the two mirrors be parallel to each other
At a certain place, the horizontal component of earth's magnetic field is $\sqrt 3$ times the vertical component. The angle of dip at that place is
→The length of the optical path of two media in contact of length $d_1$ and $d_2$ of refractive indices $\mu_1$ and $\mu_2$ respectively, is
→A $10 cm$ long perfectly conducting wire $PQ$ is moving, with a velocity $1 cm / s$ on a pair of horizontal rails of zero resistance. One side of the rails is connected to an inductor $L=1 mH$ and a resistance $K =1 \Omega$ as shown in figure. The horizontal rails, $L$ and $R$ lie in the same plane with a uniform magnetic field $B =1 T$ perpendicular to the plane. If the key $S$ is closed at certain instant, the current in the circuit after 1 millisecond is $x \times 10^{-3} A$, where the value of $x$ is. . . . . . [Assume the velocity of wire $PQ$ remains constant $(1 cm / s )$ after key $S$ is closed. Given : $e ^{-1}=0.37$, where $e$ is base of the natural logarithm]
→In the following star circuit diagram (figure), the equivalent resistance between the points $A$ and $H$ will be ..............$r$
→A uniform wire of length $l$ and radius $r$ has a resistance of $100\, \Omega $. It is recast into a wire of radius $\frac{r}{2}$. The resistance of new wire will be ............... $\Omega$
→A vessel of depth $2d\, cm$ is half filled with a liquid of refractive index ${\mu _1}$ and the upper half with a liquid of refractive index ${\mu _2}$. The apparent depth of the vessel seen perpendicularly is
→The total current supplied to the circuit by the battery is
The unit of susceptance is.
Two circular coils $P$ and $Q$of $100$ turns each have same radius of $\pi \mathrm{cm}$. The currents in $\mathrm{P}$ and $\mathrm{R}$ are $1 \mathrm{~A}$ and $2 \mathrm{~A}$ respectively. $\mathrm{P}$ and $\mathrm{Q}$ are placed with their planes mutually perpendicular with their centers coincide. The resultant magnetic field induction at the center of the coils is $\sqrt{\mathrm{x}} \mathrm{mT}$, where X=___.
→$\left[\text { Use } \mu_0=4 \pi \times 10^{-7} \mathrm{TmA}^{-1}\right]$