- A${K_2}\left[ {PtC{l_6}} \right]$
- ✓$\left[ {Co{{\left( {N{H_3}} \right)}_3}{{(N{O_2})}_3}} \right]$
- C${K_4}\left[ {Fe{{\left( {CN} \right)}_6}} \right]$
- D$\left[ {Cu{{\left( {N{H_3}} \right)}_4}} \right]S{O_4}$
$\left[ Co \left( NH _{3}\right)_{3}\left( NO _{2}\right)_{3}\right]=$ out of the coordination sphere no ions (non ionisable) $K_{4}\left[F e(C N)_{6}\right]=5$ ions
$\left[ Co \left( NH _{3}\right)_{4}\right] . SO _{4}=2$ ions
More ions $\propto$ more conductivity
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Formula
$2 \mathrm{Fe}^{3+}(\mathrm{aq})+2 \mathrm{I^-}(\mathrm{aq}) \rightarrow 2 \mathrm{Fe}^{2+}(\mathrm{aq})+\mathrm{I}_{2}(\mathrm{aq})$
$\mathrm{E}_{\text {call }}^{\mathrm{e}}=0.24 \mathrm{V}$ at $298\; \mathrm{K}$. The standard Gibbs energy $\left( {{\Delta _r}{{\rm{G}}^ \ominus }} \right)$ of the cell reaction is:
[Faraday constant $\mathrm{F}=96500 \;\mathrm{C} \mathrm{mol}^{-1} $]