MCQ
Points $(-2, 4, 7), (3, -6, -8)$ and $(1, -2, -2)$ are
- ✓Collinear
- BVertices of an equilateral triangle
- CVertices of an isosceles triangle
- DNone of these
==> $ - \frac{5}{2} = - \frac{5}{2} = - \frac{5}{2}$ Obviously, points are collinear.
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| $\text{X}:$ | $2$ | $3$ | $4$ | $5$ |
| $\text{P}(\text{X}):$ | $\frac{5}{\text{k}}$ | $\frac{7}{\text{k}}$ | $\frac{9}{\text{k}}$ | $\frac{11}{\text{k}}$ |
The value of k is: