MCQ
Product $(A)$ is


- A

- B

- ✓

- D








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$C{H_3}CHO\mathop {\xrightarrow{{(i)\,NaCN/HCl}}}\limits_{(ii)\,{H_2}O/{H^ \oplus }/\Delta } (A)\mathop {\xrightarrow{{Fenton}}}\limits_{reagent} (B)$
$(B)$ will be :
Sucrose $\quad$ $\quad$ $\quad$ $\quad$ $\quad$ $\quad$ $\quad$ Glucose $\quad$ Fructose
$C _{6} H _{12} O _{6} \stackrel{\text { Enzyme B }}{\longrightarrow} 2 C _{2} H _{5} OH +2 CO _{2}$
Glucose
In the above reactions, the enzyme $A$ and enzyme $B$ respectively are :-
| List-$I$ | List-$II$ |
| $\mathrm{P}_2 \mathrm{O}_3+3 \mathrm{H}_2 \mathrm{O} \rightarrow$ | $\mathrm{P}(\mathrm{O})\left(\mathrm{OCH}_3\right) \mathrm{Cl}_2$ |
| $\mathrm{P}_4+3 \mathrm{NaOH}+3 \mathrm{H}_2 \mathrm{O} \rightarrow$ | $\mathrm{H}_3 \mathrm{PO}_3$ |
| $\mathrm{PCl}_5+\mathrm{CH}_3 \mathrm{COOH} \rightarrow$ | $\mathrm{PH}_3$ |
| $\mathrm{H}_3 \mathrm{PO}_2+2 \mathrm{H}_2 \mathrm{O}+4 \mathrm{AgNO}_3 \rightarrow$ | $\mathrm{H}_3 \mathrm{PO}_4$ |