MCQ
Product $(A)$ of reaction is


- A

- B

- ✓

- D








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$XeF_6 + H_2O \rightleftharpoons XeOF_4 + 2HF, \,\,\,\,K_1$
$XeO_4 + XeF_6 \rightleftharpoons XeOF_4 + XeO_3F_2,\,\,\,\, K_2$
The equilibrium constant for the reaction
$XeO_4 + 2HF \rightleftharpoons XeO_3F_2 + H_2O$ will be
(Given that : $SrCO_{3(s)} \rightleftharpoons SrO_{(s)}+ CO_{2(g)} \,, K_p=1.6\,atm$)