MCQ
Product $(B)$ of above reaction is


- A

- ✓

- C

- D








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$(i)\,\, Cl^-$ can give up an electron more easily than $F^-$
$(ii) \,\,Cl^-$ is a better reducing agent than $F^-$
$(iii)\,\, Cl^-$ is smaller in size than $F^-$
$(iv)\,\, F^-$ can be oxidized more readily than $Cl^-$