MCQ
Sodium hydroxide solution reacts with phosphorus to give phosphine. To bring about this reaction, we need
- ✓White phosphorus and dil. $NaOH$
- BWhite phosphorus and conc. $NaOH$
- CRed phosphorus and dil. $NaOH$
- DRed phosphorus and conc. $NaOH$
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$\left[\right.$ Given $\left.: \log _{10} 2=0.301, \ln 10=2.303\right]$
$CHCl_3\xrightarrow[hv]{O_2}[A]\xrightarrow{EtOH}[B]\xrightarrow{2\ mole\ MeMgBr}$
$[C]\xrightarrow{CaOCl_2}[D]\xrightarrow{\Delta}CH_3-\underset{\underset{O}{||}}{C}-CH_3$