MCQ
Product $(D)$ will be


- A

- ✓

- C

- D








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$\frac{d[NH_3]}{dt} = 2 \times 10^{-4} \, mol \,L^{-1} \, s^{-1}$ , the value of $\frac{-d[H_2]}{dt}$ would be .................. $mol \,L^{-1} \, s^{-1}$
