MCQ
Product of this Hoffmann bromamide reaction is


- A$\begin{matrix}
O\,\, \\
||\,\, \\
Ph-C-C{{H}_{3}} \\
\end{matrix}$ - ✓$Ph-CHO$
- C

- D$Ph-CH_2 -NH_2$


Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
| $LIST-I$ $(Substances)$ | $LIST-II$ $(Element Present)$ |
| $A$. Ziegler catalyst | $I$. Rhodium |
| $B$. Blood pigment | $II$. Cobalt |
| $C$ .Wilkinson catalyst | $III$. Iron |
| $D$. Vitamin $\mathrm{B}_{12}$ | $IV$. Titanium |
Choose the correct answer from the options given below:
$\mathrm{H}_3 \mathrm{PO}_4 \ \ \ \ \mathrm{H}_2 \mathrm{SO}_4 \ \ \ \ \mathrm{H}_3 \mathrm{PO}_3 \ \ \ \ \mathrm{H}_2 \mathrm{CO}_3 \ \ \ \ \mathrm{H}_2 \mathrm{~S}_2 \mathrm{O}_7 $
$ \mathrm{H}_3 \mathrm{BO}_3 \ \ \ \ \mathrm{H}_3 \mathrm{PO}_2 \ \ \ \ \mathrm{H}_2 \mathrm{CrO}_4 \ \ \ \ \mathrm{H}_2 \mathrm{SO}_3 $