MCQ
Projection of vector $\vec A$ on $\vec B$ is
  • A
    $\vec A.\vec B$
  • $\vec A.\hat B$
  • C
    $\vec B \times \vec A$
  • D
    $\hat B.\hat A$

Answer

Correct option: B.
$\vec A.\hat B$
b
$A\,\cos \,\theta  = \frac{{\vec A.\vec B}}{{\left| {\vec B} \right|}} = \vec A.\hat B$

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