Question
Prove that $\sin( 90^\circ - \theta ) \sin \theta \cot \theta = \cos^2\theta .$
✓
Answer
$LHS = \sin( 90^\circ - \theta ) \sin \theta \cot \theta$
$= \cos \theta . \sin \theta $.$\frac{\cos \theta}{\sin \theta}$
$= \cos^2\theta$
$= RHS$
Hence proved.
$= \cos \theta . \sin \theta $.$\frac{\cos \theta}{\sin \theta}$
$= \cos^2\theta$
$= RHS$
Hence proved.
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