Question
Prove that:
$\frac{\sin\theta}{\cos(90^\circ-\theta)}+\frac{\cos\theta}{\sin(90^\circ-\theta)}=2$
$\frac{\sin\theta}{\cos(90^\circ-\theta)}+\frac{\cos\theta}{\sin(90^\circ-\theta)}=2$
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Prove the following identites:
$\big(1-\cos^2\theta\big)\text{cosec}^2\theta=1$