MCQ
Radius of the first Bohr’s orbit of hydrogen atom is ............. $\mathrm{A}$
- A$1.06$
- B$0.22$
- C$0.28$
- ✓$0.53$
$r = \frac{{{n^2} \times 0.529{A}}}{z}$; where $z =$ Atomic number,
$n = $ Number of orbitals
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$CO_{2(g)} + C_{(s)} \to 2CO_{(g)}$