MCQ
Reagent $(A)$ and $(B)$ in above reaction are


- A$A = RCO_3 H , B = H_2O_2$
- B$A = RCO_3H , B = HIO_4$
- ✓$A = RCO_3 H, B = O_3$
- D$A = O_3 , B = RCO_3H$

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Statement $(I)$ : The $4 \mathrm{f}$ and $5 \mathrm{f}$ - series of elements are placed separately in the Periodic table to preserve the principle of classification.
Statement $(II)$ :$S$-block elements can be found in pure form in nature. In the light of the above statements, choose the most appropriate answer from the options given below :