MCQ
Reversibility is not possible because of:
- AResistive force present everywhere.
- BEvery process around us is Quasi-static.
- CGases are viscous.
- DGases have density.
✓
Answer
- Resistive force present everywhere.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Consider two wires of same material having their ratio of radii to be $2: 1$. If these two wires are stretched by equal force, then the ratio of stress produced in them is
→Each of the three graphs represents acceleration versus time for an object that already has a positive velocity at time $t_1$. Which graphs show an object whose speed is increasing for the entire time interval between $t_1$ and $t_2$ ?
→A mass $M$ is suspended from a light spring. An additional mass m added displaces the spring further by a distance $x$. Now the combined mass will oscillate on the spring with period
→The $K.E.$ and $P.E.$ of a particle executing $SHM$ with amplitude $A$ will be equal when its displacement is
→If the gravitational acceleration at surface of Earth is $g,$ then increase in potential energy in lifting an object of mass $m$ to a height equal to half of radius of earth from surface will be
→The least count of the main scale of a screw gauge is $1\, mm$. The minimum number of divisions on its circular scale required to measure $5\,\mu m$ diameter of a wire is
→There is a rough black spot on a polished metallic plate. It is heated upto $1400 K$ approximately and then at once taken in a dark room. Which of the following statements is true
→A block is kept on an inclined plane of inclination $\theta$ of length l. The velocity of particle at the bottom of inclined is (the coefficient of friction is $\mu$)
→If a ladder weighing $250\,N$ is placed against a smooth vertical wall having coefficient of friction between it and floor is $0.3$, then what is the maximum force of friction available at the point of contact between the ladder and the floor ........ $N$
→The acceleration of a particle starting from rest, varies with time according to the relation $A = -a\omega^2 sin\omega t.$ The displacement of this particle at a time $t$ will be
→