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$\begin{array}{*{20}{c}}
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,}\\
{\,\,\,\,\,\,\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3} - C - CH = C{H_2}}\\
{\,|\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,}\\
{C{H_3}\,\,\,\,\,\,\,\,\,\,\,\,\,}
\end{array}$ $\xrightarrow{{{H_2}O/{H^ \oplus }}}$ $\mathop A\limits_{{\rm{(major)}}} $ + $\mathop B\limits_{{\rm{(minor)}}} $
The major product is
$(a)$ Octahedral $Co(III)$ complexes with strong field ligands have very high magnetic moments
$(b)$ When $\Delta_{0}< P$, the $d-$electron configuration of $Co(III)$ in an octahedral complex is $t_{\text {eg }}^{4} e_{g}^{2}$
$(c)$ Wavelength of light absorbed by $\left[\mathrm{Co}(\mathrm{en})_{3}\right]^{3+}$ is lower than that of $\left[\mathrm{CoF}_{6}\right]^{3-}$
$(d)$ If the $\Delta_{0}$ for an octahedral complex of $\mathrm{Co}(\mathrm{III})$ is $18,000 \;\mathrm{cm}^{-1},$ the $\Delta_{\mathrm{t}}$ for its tetrahedral complex with the same ligand will be $16,000\;\mathrm{cm}^{-1}$
(Plank's const. $ h = 6. \times 10^{-34}\, Js\,;$ mass of electron $= 9.1091 \times 10^{-31}\, kg\,;$ charge of electron $e= 1.60210 \times 10^{-19}\, C\,;$ permittivity of vaccum $\epsilon _0 = 8.854185 \times 10^{-12} \,kg^{-1} \,m^{-3} A^2$)
