Question
Show that $x = -3$ is a solution of $x^2+6 x+9=0$.

Answer

The given equation is $x^2+6 x+9=0$
If $x=-3$ is its solution then it will satisfy it.
$ \text { L.H.S. }=(-3)^2+6(-3)+9 $
$ =9-18+9 $
$ =18-18 $
$ =0 $
$ =\text { R.H.S. }$
Hence $x=-3$ is its one root.

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