Question
Solve the following quadratic equation:
$ 9 x^2-3 x-2=0 $
$ 9 x^2-3 x-2=0 $
✓
Answer
$ 9 x^2-3 x-2=0 $
$ \Rightarrow 9 x^2-6 x+3 x-2=0 $
$ \Rightarrow 3 x(3 x-2)+1(3 x-2)=0 $
$ \Rightarrow(3 x-2)(3 x+1)=0 $
$ \Rightarrow 3 x-2=0 \text { or } 3 x+1=0$
$\Rightarrow\text{x}=\frac{2}{3}$ or $\text{x}=-\frac{1}3{}$
$ \Rightarrow 9 x^2-6 x+3 x-2=0 $
$ \Rightarrow 3 x(3 x-2)+1(3 x-2)=0 $
$ \Rightarrow(3 x-2)(3 x+1)=0 $
$ \Rightarrow 3 x-2=0 \text { or } 3 x+1=0$
$\Rightarrow\text{x}=\frac{2}{3}$ or $\text{x}=-\frac{1}3{}$
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