(Si_2O_5)_n^ 2n- anion is obtained when - Vidyadip

MCQ

$(Si_2O_5)_n^{2n-}$ anion is obtained when

A
no oxygen of a $SiO_4^{4-}$ tetrahedron is shared with another $SiO_4^{4-}$ tetrahedron
B
one oxygen of a $SiO_4^{4-}$ tetrahedron is shared with another $SiO_4^{4-}$- tetrahedron
C
two oxygen of a $SiO_4^{4-}$ tetrahedron are shared with another $SiO_4^{4-}$ tetrahedron
✓
three oxygen of a $SiO_4^{4-}$ tetrahedron are shared with another $SiO_4^{4-}$ tetrahedron

✓

Answer

Correct option: D.

three oxygen of a $SiO_4^{4-}$ tetrahedron are shared with another $SiO_4^{4-}$ tetrahedron

d
Total No. of oxygen atoms per silicon atom $=\frac{1}{2}+\frac{1}{2}+\frac{1}{2}+1=2.5$

$\therefore$ Formula $\mathrm{Si}_{2} \mathrm{O}_{5}^{2-}$

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