MCQ
$\sin[\cot^{-1}\{\cos(\tan^{-1}\text{x})\}]=$
- ✓$\sqrt{\frac{\text{x}^2+1}{\text{x}^2+2}}$
- B$\sqrt{\frac{\text{x}^2-1}{\text{x}^2-2}}$
- C$\sqrt{\frac{\text{x}-1}{\text{x}-2}}$
- D$\sqrt{\frac{\text{x}+1}{\text{x}+2}}$
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$I$. $f$ is continuous on the closed interval $[a, b]$
$II.$ $f$ is bounded on the open interval $(a, b)$
$III.$ If $a$ $< a_1< b_1< b$, and $f (a_1)<0< f (b_1)$, then there is $a$ number $c$ such that $a_1 < c < b_1$ and $f (c)=0$