MCQ
$SnCl_2$ acts as a reducing agent
- A$SnCl_2$ can accept electrons readily
- B$Sn^{2+}$ is more stable than $Sn^{4+}$
- ✓$Sn^{4+}$ is more stable than $Sn^{2+}$
- D$Sn^{2+}$ can be easily converted to metallic tin
Hence, option $\mathrm{C}$ is the correct answer.
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| List$-I$ | List$-II$ |
| $(A)$ Chloroform and Aniline | $(I)$ Steam distillation |
| $(B)$ Benzoic acid and Napthalene | $(II)$ Sublimation |
| $(C)$ Water and Aniline | $(III)$ Distillation |
| $(D)$ Napthalene and Sodium chloride | $(IV)$ Crystallisation |