MCQ
Solute when dissolved in water
- AIncreases the vapour pressure of water
- BDecreases the boiling point of water
- ✓Decreases the freezing point of water
- DAll of the above
✓
Answer
Correct option: C.
Decreases the freezing point of water
c
When a solute dissolves in water, the vapour pressure of the solvent decreases and because of this boiling point increases and freezing point decreases.
When a solute dissolves in water, the vapour pressure of the solvent decreases and because of this boiling point increases and freezing point decreases.
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
During an electrolysis of conc. $H_2SO_4$ , perdisulphuric acid $(H_2S_2O_8)$ and $O_2$ form in equimolar amount. The amount of $H_2$ that will form simultaneously will be $(2{H_2}S{O_4} \to {H_2}{S_2}{O_8} + 2{H^ + } + 2{e^ - })$
→$C$ is ?
→Which of the following oxy acids of phosphorus is a reducing agent and monobasic
Given below are two statements :
→Statement $I :$ The boiling points of the following hydrides of group $16$ elements increases in the order -
$H _{2} O < H _{2} S < H _{2} Se < H _{2} \text { Te. }$
Statement $II :$ The boiling points of these hydrides increase with increase in molar mass.
In the light of the above statements, choose the most appropriate answer from the options given below
Correct order for nucleophilic addition reaction :
→$(1)$ $\begin{matrix}
O \\
|| \\
{{C}_{6}}{{H}_{5}}-C-{{C}_{6}}{{H}_{5}} \\
\end{matrix}$
$(2)$ $C _{6} H _{5}- CHO$
$(3)$ $p - CH _{3}- C _{6} H _{4}- CHO$
$(4)$ $p - CH _{3} O - C _{6} H _{4}- CHO$
Which is most reactive halide towards ${{S}_{{{N}^{1}}}}$ reaction
→Silver acetate.$ + \;B{r_2}\xrightarrow{{{\text{C}}{{\text{S}}_{\text{2}}}}}\,.$ The main product of this reaction is
→Bromine is commercially prepared from sea water by displacement reaction
→$Cl_2 + 2Br^ - (aq.) \to 2Cl^-(aq.) + Br_2$
$Br_2$ gas thus formed is dissolved into solution of $Na_2CO_3$ and then pure $Br_2$ is obtained by treatment of the solution with
$[(C_6H_5)_2 Pd (SCN)_2]$ and $[(C_6H_5)_2 Pd (NCS)_2]$ are :
→When chlorine reacts with cold and dilute solution of sodium hydroxide, the products obtained are