Question
Solve for $x : 3 \tan^2 (2x - 20^\circ) = 1$
✓
Answer
$3 \tan^2 ( 2x – 20^\circ) = 1$
$\tan ( 2x – 20^\circ) =\frac{1}{\sqrt{3}}$
$\tan ( 2x – 20^\circ) = \tan 30^\circ$
$2x –20^\circ = 30^\circ$
$2x = 50^\circ$
$x = 25^\circ$
$\tan ( 2x – 20^\circ) =\frac{1}{\sqrt{3}}$
$\tan ( 2x – 20^\circ) = \tan 30^\circ$
$2x –20^\circ = 30^\circ$
$2x = 50^\circ$
$x = 25^\circ$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
More "[2 Mark Question Answer]" from Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios]→Trigonometrical Ratios of Standard Angles [Including Evaluation of an Expression Involving Trigonometric Ratios] — all question types→MATHEMATICS STD 9 question papers→ICSE Board STD 9 question papers→ICSE Board question paper generator→
Similar questions
Convert the following fractions into a decimal:
$2 \frac{5}{12}$
→$2 \frac{5}{12}$
Without using trigonometric tables, evaluate.
$\frac{\cos ^2 34^{\circ}+\cos ^2 56^{\circ}}{\sin ^2 59^{\circ}+\sin ^2 31^{\circ}}$
→$\frac{\cos ^2 34^{\circ}+\cos ^2 56^{\circ}}{\sin ^2 59^{\circ}+\sin ^2 31^{\circ}}$
Find the value of: $\log _2 8$
→Find the median of: $25, 16, 26, 16, 32, 31, 19, 28$ and $35$
→In the following, find the inclination of line $\text{AB}:$
→Expand : $(3 a b-2 c)^3$
→Evaluate the following$: \frac{\sin 62^{\circ}}{\cos 28^{\circ}}$
→Given $\log _{10} x=a, \log _{10} y=b$,
Write down $10^{2 b}$ in terms of $y$.
→Write down $10^{2 b}$ in terms of $y$.
Find the distance between the following pairs of points$:\left(\frac{3}{5}, 2\right)$ and $\left(-\frac{1}{5}, 1 \frac{2}{5}\right)$
→Solve for x:
$3^x=\frac{1}{3}$
→$3^x=\frac{1}{3}$