Question
Solve for x(x is real number), $4x + 3 < 5x + 7.$
✓
Answer
Given, $4x + 3 < 5x + 7$
Transposing $5x$ to LHS and $3$ to RHS, we get
$4x - 5x < 7 - 3$
оr, $- x < 4$
or, $x > - 4$
$\therefore$When $x$ is real, the solution is $(-4, \infty).$
Transposing $5x$ to LHS and $3$ to RHS, we get
$4x - 5x < 7 - 3$
оr, $- x < 4$
or, $x > - 4$
$\therefore$When $x$ is real, the solution is $(-4, \infty).$
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