Question
Solve the following equations
$34-6(x-5)=0$
$34-6(x-5)=0$
✓
Answer
Given, equation $34-6(x-5)=0$
On subtracting 34 from both sides, we get
$
\begin{aligned}
-34+34-6(x-5) & =0-34 \\
-6(x-5) =-34
\end{aligned}
$
On dividing by -6 both sides, we get
$
\frac{-6(x-5)}{-6}=\frac{-34}{-6} \Rightarrow x-5=\frac{+34}{6}
$
On adding $5$ to both sides. we get
$
\begin{array}{l}
x-5+5-\frac{34}{6}=5 \\
x=\frac{64}{6}=\frac{32}{3}
\end{array}
$
So, $x =\frac{64}{6}=\frac{32}{3}$, which is the required solution
On subtracting 34 from both sides, we get
$
\begin{aligned}
-34+34-6(x-5) & =0-34 \\
-6(x-5) =-34
\end{aligned}
$
On dividing by -6 both sides, we get
$
\frac{-6(x-5)}{-6}=\frac{-34}{-6} \Rightarrow x-5=\frac{+34}{6}
$
On adding $5$ to both sides. we get
$
\begin{array}{l}
x-5+5-\frac{34}{6}=5 \\
x=\frac{64}{6}=\frac{32}{3}
\end{array}
$
So, $x =\frac{64}{6}=\frac{32}{3}$, which is the required solution
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